Question

As Courtney switches on the TV set to watch her favorite cartoon, the electron beam in the TV tube is steered across the screen by the field between two charged plates. If the electron experiences a force of 3.0 × 10^-6 N, how large is the field between the deflection plates?​

Answer 1

The force experienced by the electron is given by:

F = Eq

where E is the electric field strength and q is the charge of the electron.

The charge of the electron is -1.6 × 10^-19 C.

Substituting the values, we get:

3.0 × 10^-6 N = E(-1.6 × 10^-19 C)

Solving for E, we get:

E = (3.0 × 10^-6 N) / (-1.6 × 10^-19 C)

E = -1.875 × 10^13 N/C

The magnitude of the electric field strength between the deflection plates is 1.875 × 10^13 N/C.