87.1k views
1 vote
15 points! Solve for x
(sqrt{2}+1)^x +(sqrt{2}-1)^x = 6.

User Vlasta Po
by
6.8k points

1 Answer

5 votes

Answer: x = 5.2136 or x = -1.2136

Step-by-step explanation: Let's first simplify the expression by using the identity:

(a+b)^2 = a^2 + 2ab + b^2

For this problem, let a = sqrt(2) and b = 1, so we get:

(sqrt{2}+1)^2 = 2 + 2sqrt{2} + 1 = 3 + 2sqrt{2}

Now we can rewrite the original equation as:

(sqrt{2}+1)^x + (sqrt{2}-1)^x = 6

[(sqrt{2}+1)^(x/2)]^2 + [(sqrt{2}-1)^(x/2)]^2 + 2(sqrt{2}+1)^(x/2)(sqrt{2}-1)^(x/2) = 6

Let's define a = (sqrt{2}+1)^(x/2) and b = (sqrt{2}-1)^(x/2), then the equation can be rewritten as:

a^2 + b^2 + 2ab = 6

Now we can substitute the value we found earlier for (sqrt{2}+1)^2:

a^2 + b^2 + 2ab = 3 + 2sqrt{2}

We can rewrite this as:

(a+b)^2 = 3 + 2sqrt{2}

Taking the square root of both sides, we get:

a+b = ±√(3 + 2sqrt{2})

Now we can substitute back in the expressions for a and b:

(sqrt{2}+1)^(x/2) + (sqrt{2}-1)^(x/2) = ±√(3 + 2sqrt{2})

We can solve for x/2 by taking the logarithm of both sides:

log[(sqrt{2}+1)^(x/2) + (sqrt{2}-1)^(x/2)] = log[±√(3 + 2sqrt{2})]

x/2 = 2.6068 or -0.6068

Multiplying both sides by 2, we get:

x = 5.2136 or -1.2136

Therefore, the solutions are:

x = 5.2136 or x = -1.2136.

User BangOperator
by
8.6k points