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How many moles of air must there be in a bicycle tire with a volume of 2.67 L if it has an internal pressure of 7.30 atm at 17.0°C?

User Ksun
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Answer: .819 Moles of Air

Explanation: To solve this problem, we will use the Ideal Gas Law which states that PV=nRT. P represents pressure or internal pressure, V is volume, T is temperature, n is moles of a gas, and R is the Universal Gas Constant. For the ideal gas law, R is .08206. R is 8.314 for any other calculation. We are solving for the moles of gas. The gas in this case is air which is a mixture of gases but that isn't important.

Our givens are P = 7.3 atm, V = 2.67 L and T = 17.0°C. We convert T to Kelvin because the Ideal Gas Law requires that. We simply add 273 to the value in Celcius to convert it to Kelvin. Our T is now 290 K. We also know R is our Universal Gas Constant. We can now plug into the law.

(7.3 atm)(2.67 L) = n(.08206)(290 K)

n = ((7.3 atm)(2.67 L))/(.08206)(290 K)

n = .819 moles of air

Hope this helps!

User Sunding Wei
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