Question

A marshmallow is placed in a microwave to be heated for smores. The marshmallow has a 86 mL at a temperature of 543 °C. What temperature, in K, would the

marshmallow need to be if the volume changed to 51.1 ml?

Answer 1

Answer: We can use the combined gas law to solve this problem:

(P₁V₁/T₁) = (P₂V₂/T₂)

where P is pressure, V is volume, and T is temperature in Kelvin.

We know that P₁ = P₂ (the pressure is assumed to be constant), and we are given V₁, T₁, and V₂. We can solve for T₂:

(P₁V₁/T₁) = (P₂V₂/T₂)

T₂ = (P₂V₂/T₁) * (T₁/P₁V₁)

We need to convert the initial temperature from Celsius to Kelvin:

T₁ = 543 + 273 = 816 K

Substituting the values:

T₂ = (1 atm * 86 mL / 816 K) * (51.1 mL / 1 atm * 86 mL)

T₂ = 0.0629 * 51.1 * 1000 = 3217 K

Therefore, the marshmallow would need to be heated to a temperature of 3217 K for its volume to change from 86 mL to 51.1 mL.

Enjoy (:

Answer 2

Answer: 484.94 K

Step-by-step explanation:

T2 = T1 X V2 / V1

Temperature must be in kelvin so 543 + 273.15 =816.15

816.15 X 51.1 / 86