Answer:
The pressure of the gas at 0.0 °C is 1.84 atm.
Step-by-step explanation:
To solve this problem, we can use the combined gas law, which states that the equation relates the pressure, volume, and temperature of a gas:
(P1 x V1) / T1 = (P2 x V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
We are given:
P1 = 3.25 atm
T1 = 210.0 °C = 483.15 K (convert to Kelvin)
T2 = 0.0 °C = 273.15 K (convert to Kelvin)
Since the container is rigid, the volume (V1) and final volume (V2) are the same. Therefore, we can simplify the equation to:
P1 / T1 = P2 / T2
Substituting the given values, we get:
(3.25 atm) / (483.15 K) = P2 / (273.15 K)
Simplifying, we get:
P2 = (3.25 atm x 273.15 K) / 483.15 K
P2 = 1.84 atm