Question

Set 1 - Use the balanced chemical equation for the production of rust to solve:

4 Fe + 3 O2 → 2 Fe2O3
If you produced 0.00521 moles Fe2O3, how many moles of Fe were reacted?

If you need to produce 1.867 mol Fe2O3, how many moles O2 are needed to react?

Given 9.54 mol Fe, how many moles O2 will be needed?

Given 0.578 mol O2, how many moles Fe will be needed to react completely?

Answer 1

Step-by-step explanation:

0.01042 moles Fe --how to calculate (0.00521/2 moles X 4 moles) the 2 and 4 are the coefficients in the chemical equation

2.8005 moles O2-- how to calculate (1.867 / 2 X 3 moles O2)

7.155 moles Fe calculate it this way (9.54 / 4 moles Fe X 3 moles O2

0.7707 moles Fe ---(0.578 / 3 moles O2 X 4 moles Fe)