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54. Sally has an average score of exactly k points on 6 equally

weighted tests. How many points higher than k must Sally
score on the 7th equally weighted test to raise her average
score after the 7th test to k + 2.5 points?

PLEASE SHOW WORK

1 Answer

4 votes

Answer:

Sally's score on the 7th test needs to be 17.5 points points more than the average of her first 6 tests.

Explanation:

Let T be the sum of the scores of Sally's first 6 tests. Her average score would be:

Avg. Score (S) =T/6

Let S stand for Sally's average score.

We are told her average is k, so we can write: S = k

Let N stand for the score of her New (7th) test. Her total score would be:

T + N [This is the sum of all 7 of her tests]

Her average would become (T+N)/7

The goal is to raise her average score by 2.5 points to (k+2.5) points.

That means (T+N)/7 = k+2.5 [Her new average is 2.5 points higher]

(T + N)/7 = k + 2.5

T+N = 7k+17.5

Note that T = 6k [her total score for the first 6 tests is her average, k, times 6]

We'll use this definition of T in the equation:

T+N = 7k+17.5

(6k)+N = 7k+17.5 [Substitute 6k for T, since T=6k]

N = 7k+17.5-6k [Rearrange]

N = 1k+17.5

This is telling Sally, and us, that her new test, N, must score 17.5 points higher than her average score, k.

The answer is 17.5 points.

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