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If 2a+b=7 and b+2c=23 what is the mean of a,b,c

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Answer:To find the mean of a, b, and c, we first need to determine their individual values.

We can use the two given equations to solve for a, b, and c:

2a + b = 7 (equation 1)

b + 2c = 23 (equation 2)

Solving for b in equation 1, we get:

b = 7 - 2a

Substituting this value of b into equation 2, we get:

7 - 2a + 2c = 23

Simplifying this equation, we get:

2c - 2a = 16

Dividing both sides by 2, we get:

c - a = 8

Solving for c in terms of a, we get:

c = a + 8

Now, we can substitute this expression for c into equation 2 to solve for b:

b + 2c = 23

b + 2(a + 8) = 23

b + 2a + 16 = 23

b + 2a = 7

Substituting the value of b from equation 1 into this equation, we get:

7 - 2a + 2a = 7

Therefore, we have found that:

b = 7 - 2a

c = a + 8

To find the mean of a, b, and c, we can add these values together and divide by 3:

mean = (a + b + c) / 3

Substituting the expressions we found for b and c, we get:

mean = (a + (7 - 2a) + (a + 8)) / 3

Simplifying this equation, we get:

mean = (3a + 15) / 3

mean = a + 5

Therefore, the mean of a, b, and c is equal to a + 5. We do not have enough information to determine the specific values of a, b, and c, so we cannot determine the exact value of the mean.

Explanation:

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