Answer:
a. Z=1.98
Assuming a one-tailed test, we need to find the area to the right of the Z-score in the standard normal distribution table. The p-value can be calculated as:
p-value = 1 - P(Z ≤ 1.98)
Using a standard normal distribution table, we can find that the area to the left of 1.98 is 0.9761. Therefore,
p-value = 1 - 0.9761 = 0.0239
b. Z=2.49
Assuming a one-tailed test, we need to find the area to the right of the Z-score in the standard normal distribution table. The p-value can be calculated as:
p-value = 1 - P(Z ≤ 2.49)
Using a standard normal distribution table, we can find that the area to the left of 2.49 is 0.9934. Therefore,
p-value = 1 - 0.9934 = 0.0066
c. z=-1.02
Assuming a one-tailed test, we need to find the area to the left of the Z-score in the standard normal distribution table. The p-value can be calculated as:
p-value = P(Z ≤ -1.02)
Using a standard normal distribution table, we can find that the area to the left of -1.02 is 0.1562. Therefore,
p-value = 0.1562