Answer: The equation of a line can be written in slope-intercept form as:
y = mx + b
where m is the slope and b is the y-intercept.
We are given that the line has a slope of -3 and passes through the point (2, 2). We can use the point-slope form of the equation of a line to find the equation of this line:
y - y1 = m(x - x1)
where (x1, y1) is the given point and m is the slope.
Substituting the given values, we get:
y - 2 = -3(x - 2)
Expanding the right side:
y - 2 = -3x + 6
Adding 2 to both sides:
y = -3x + 8
Therefore, the equation of the line that has a slope of -3 and passes through the point (2, 2) is:
y = -3x + 8.
So the correct answer is:
y = -3x + 8
Explanation: