68.8k views
1 vote
what is the acceleration of a bus whose speed changes from 126 m/s to 306 m/s over a period of 3seconds

1 Answer

4 votes

Answer: The acceleration of the bus can be calculated using the formula:

a = (v2 - v1) / t

where:

a = acceleration

v2 = final velocity = 306 m/s

v1 = initial velocity = 126 m/s

t = time = 3 seconds

Substituting the given values into the formula, we get:

a = (306 m/s - 126 m/s) / 3 s

a = 180 m/s / 3 s

a = 60 m/s^2

Therefore, the acceleration of the bus is 60 m/s^2.

Explanation:

User Jit B
by
7.2k points