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A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21°C. How many moles of gas are present?

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Answer:

0.064 moles

Step-by-step explanation:

First, we need to convert the temperature in Kelvin, which can be done by adding 273 to the temperature in Celsius. So the temperature in Kelvin is 294 K. We can now use the Ideal Gas Law, PV = nRT, to solve for the number of moles, n. Rearranging the equation gives us n = PV/RT. Plugging in our values gives us n = (0.553 atm)(1.90 L)/[(0.0821 L·atm/K·mol)(294 K)] = 0.064 mol. Therefore, there are 0.064 moles of krypton gas present in the container.

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