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There is a mound of g pounds of gravel in a quarry. throughout the day, 300 pounds of gravel is added to the mound. two orders of 600 pounds are sold and the gravel is removed from the mound. at the end of the day, the mound has 1400 pounds of gravel.

solve for g.

User Serhat
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2 Answers

4 votes

Answer:

2000 pounds

Explanation:

sorry it took a while;)

User Casablanca
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4 votes

Answer:

2000 pounds

Explanation:

Let's start with the initial amount of gravel in the mound, which is g pounds.

After 300 pounds are added, the total amount of gravel in the mound becomes:

g + 300

Then, two orders of 600 pounds are sold and removed from the mound. So, the total amount of gravel in the mound after these two orders are sold becomes:

g + 300 - 2(600) = g + 300 - 1200 = g - 900

Finally, we know that at the end of the day, the mound has 1400 pounds of gravel. So, we can set up an equation:

g - 900 + 300 = 1400

Simplifying this equation, we get:

g - 600 = 1400

Adding 600 to both sides, we get:

g = 2000

Therefore, the initial amount of gravel in the mound was 2000 pounds.

User Peter Sarnowski
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