Question

Find the slope of the tangent to thefunction f(x) = 2x4 + 6x² +4 at x = -1

Answer 1

-20

Explanations:

Given the function f(x) = 2x^4 + 6x^2 + 4 at x = 1, the slope of the tangent of the function is expressed as:

`f^(\prime)(x)=8x^3+12x`

Substitute the value of x = -1 into the fucntion

`\begin{gathered} f^(\prime)(-1)=8(-1)^3+12(-1) \\ f^(\prime)(-1)=8(-1)-12 \\ f^(\prime)(-1)=-8-12 \\ f^(\prime)(-1)=-20 \end{gathered}`

Hence the slope of the tangent to the function at x = -1 is -20