Question

3) The height of a ball above the ground t seconds after it is thrown is h(t) = 20 + 32t - 16t².

a) How long will it take for the ball to hit the ground?
b) How long does it take to reach its maximum height?
c) What is the ball's maximum height?
d) If the ball was thrown from a height of 30 feet what would the equation be?

Answer 1

Answer:It will hit the ground when 84 - 16t^2 = 0

Explanation:

16t^2 = 84

t^2 = 5.25

t = 2.29