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A girl leaves a sandwich out for an experiment. After 4 days she sees that there are 71 bacteria. 3 days after that, she sees that there are 185 bacteria. Write an exponential equation to represent this situation.

The girl estimates that once there are 500 bacteria, the sandwich will be fully covered. How long, in days, will it take to reach 500 bacteria?

User Afshar
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Answer:

approximately 10.3 days to reach 500 bacteria

Explanation:

Let's use the formula for exponential growth to write an equation that represents the situation: N = N0 * e^(rt)

where N is the number of bacteria, N0 is the initial number of bacteria, e is Euler's number (approximately 2.718), r is the growth rate, and t is the time in days.

We know that after 4 days, the number of bacteria is 71, so we can plug these values into the equation to solve for the growth rate: 71 = N0 * e^(4r)

Similarly, after 7 days (4 + 3), the number of bacteria is 185: 185 = N0 * e^(7r)

Now we have two equations with two unknowns (N0 and r). We can divide the second equation by the first equation to eliminate N0: 185/71 = e^(3r)

Taking the natural logarithm of both sides, we get: ln(185/71) = 3r

Solving for r, we get: r = ln(185/71) / 3 ≈ 0.558

Now we can use the first equation and the growth rate we just found to solve for N0:

71 = N0 * e^(4 * 0.558)

N0 ≈ 11.7

So the initial number of bacteria was approximately 11.7.

To find out how long it will take to reach 500 bacteria, we can plug in the values we know into the equation and solve for t: 500 = 11.7 * e^(0.558t)

Dividing both sides by 11.7, we get: e^(0.558t) ≈ 42.74

Taking the natural logarithm of both sides, we get: 0.558t ≈ ln(42.74)

Solving for t, we get: t ≈ ln(42.74) / 0.558 ≈ 10.3 days

Therefore, it will take approximately 10.3 days for the sandwich to be fully covered with bacteria.

User Marita
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