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If the brine contains 138 g of NaCl, how much Cl2 can be produced?

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Answer:

167.5g

Step-by-step explanation:

From the question, we know the mass of NaCl and the molar mass of NaCl, so we can calculate the number of moles of NaCl:

Moles = mass ÷ molar mass

The molar mass of NaCl can be calculated by adding the relative formula masses of the elements Na and Cl:

23.0 + 35.5 = 58.5

We can use the formula to find the number of moles of NaCl:

moles = 138 ÷ 58.5

= 2.35897...

Now, we need to find the mass of Cl2. Rearranging the formula of moles = mass ÷ molar mass

mass = moles × molar mass

Calculating the molar mass of Cl2 by adding the relative atomic masses:

35.5 + 35.5 = 71

Hence the mass is:

2.35897... × 71 = 167.5g (to 1dp)

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