Answer:
see attached
Explanation:
You want the graph of f(x) = 1/2(2^x).
Points
You can find a few points on the graph using small integer values of x.
f(-1) = 1/2(2^-1) = 1/4
f(0) = 1/2(2^0) = 1/2
f(1) = 1/2(2^1) = 1
f(2) = 1/2(2^2) = 2
f(3) = 1/2(2^3) = 4
The function is exponential, so will have a horizontal asymptote of y = 0.
The graph is shown in the attachment.
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