Question

Solve for y.2y^2 - 10y + 44=(y-7)^2If there is more than one solution, separate them with commas.

Answer 1

y=-5,y=1

Explanation:

To solve this, we need to solve a quadratic equation, using the bhaskara formula.

Initially, let's place the equation in the standard format. So

`2y^2-10y+44=(y-7)^2`
`2y^2-10y+44=y^2-14y+49`
`2y^2-y^2-10y+14y+44-49=0`
`y^2+4y-5=0`

Now we apply the bhaskara formula:

`y=(-(4)\pm√(4^2-4\ast1\ast-5))/(2\ast1)`

Then

`y=(-4\pm6)/(2)`

So two solutions:

`y^{^(\prime)}=(-4+6)/(2)=1,y^{^(\prime)^(\prime)}=(-4-6)/(2)=-5`

The solution are y=-5,y=1