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1 vote
Two charges, Q1

= 10 nC
and Q2
= -3.0 nC
, are 15 cm
apart. Find the strength of the electric field halfway between the two charges.
Express your answer with the appropriate units.

User Humbletim
by
8.1k points

1 Answer

7 votes

Step-by-step explanation:

E1 = k Q1 / (0.075 m)^2

= 9 x 10^9 Nm^2/C^2 * 10 x 10^-9 C / 0.075^2 m^2

= 400 N/C

E2 = k Q2 / (0.075 m)^2

= 9 x 10^9 Nm^2/C^2 * (-3 x 10^-9 C) / 0.075^2 m^2

= -120 N/C

Since the electric fields due to the two charges are in opposite directions, we can find the net electric field at the midway point by taking the difference between the two:

E = E1 - E2

= 400 N/C - (-120 N/C)

= 520 N/C

User Ratikanta Patra
by
8.8k points