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Write an exponential function (y=ab^x) whose graph passes through the points (2,16) and (5,128)

User Awdk
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To write an exponential function in the form of y = ab^x that passes through two given points (x1, y1) and (x2, y2), we need to first find the values of a and b.

Using the point (2, 16), we get:

16 = ab^2

Using the point (5, 128), we get:

128 = ab^5

We can divide the second equation by the first equation to eliminate a:

(128/16) = (ab^5)/(ab^2)

8 = b^3

Taking the cube root of both sides gives:

b = 2

Now we can substitute this value of b into either equation to solve for a. Using the first equation:

16 = ab^2

16 = a(2^2)

16 = 4a

a = 4

Therefore, the exponential function that passes through the points (2, 16) and (5, 128) is:

y = 4(2^x)
User PiotrNycz
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Answer:

Well question is not clear rewrite

User Sbeam
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