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What is the de Broglie wavelength (in m) of a 0.053 g object moving at a speed of 0.16 m/s?

User Ourjamie
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Answer:

The equation gives the de Broglie wavelength of an object:

λ = h / p

Where λ is the de Broglie wavelength, h is Planck's constant (6.626 x 10^-34 J s), and p is the object's momentum.

The momentum of an object can be calculated using the equation:

p = m * v

Where m is the mass of the object and v is its velocity.

In this case, the mass of the object is 0.053 g, which is equivalent to 0.053 x 10^-3 kg. The velocity of the object is 0.16 m/s. So, the momentum of the object is:

p = (0.053 x 10^-3 kg) * (0.16 m/s) = 8.48 x 10^-6 kg m/s

Substituting this value of momentum and Planck's constant into the de Broglie wavelength equation, we get:

λ = (6.626 x 10^-34 J s) / (8.48 x 10^-6 kg m/s)

Simplifying, we get:

λ = 7.82 x 10^-28 m

Therefore, the de Broglie wavelength of a 0.053 g object moving at a speed of 0.16 m/s is 7.82 x 10^-28 m.

Step-by-step explanation:

User Toodoo
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