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At what temperature will 65 g of Neon gas (Ne) occupy 12.30 liters at 1256 torr?

Explain the process.

1 Answer

5 votes

Answer:

T

=

447

K

174

C

.

Step-by-step explanation:

This is what we're given:

P

(pressure), which is

1.95 atm

.

V

(volume), which is

12.30 L

.

n

(number of moles), which is

0.654

moles of neon gas.

We have to find

T

, or temperature. To do this, we'll need to use the Ideal Gas Law, which is:

P

V

=

n

R

T

Rearranging this equation to get temperature on one side, we get:

T

=

P

V

n

R

Pressure is in

a

t

m

and volume is in

L

. This tells us that we'll need to use the value of

0.08206 L atm/K mol

for

R

, the ideal gas constant.

Plugging in all of the values, we can solve for temperature:

T

=

p

V

n

R

T

=

1.95

atm

×

12.30

L

0.654

mol

×

0.08206

L

atm

K

1

mol

T

=

447

K

We can then convert to celsius, which equals to around

174

C

.

Answer link

Step-by-step explanation: