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What is the area of a rectangle that has sides measuring (7x-1) units and (2x+3)​

2 Answers

1 vote

Answer:

14x^2+19x-3

Explanation:

you have to times them together so

(7x-1)(2x+3)

14x^2+21x-2x-3

=14x^2+19x-3

User Rytmis
by
7.7k points
5 votes

Explanation:

The area A of a rectangle is given by multiplying its length and width. In this case, the length is 7x - 1 units and the width is 2x + 3 units. Therefore, the area of the rectangle is:

A = (7x - 1)(2x + 3)

= 14x^2 + 19x - 3

Hence, the area of the rectangle is 14x^2 + 19x - 3 square units.

User Greg Thatcher
by
7.3k points