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20 POINTSS!! HURRY!

Airplane A traveled 1662 miles in six hours.

For Airplane B, y =
922/
3

x represents its rate of speed over the same six hours.





Compare the two airplanes to determine which airplane traveled at a faster rate?

Group of answer choices

Airplane A

Airplane B

User Shpresa
by
7.4k points

1 Answer

4 votes

airplane A

To compare the rate of speed of Airplane A and Airplane B, we need to calculate the speed of Airplane B first.

The formula to calculate distance is:

distance = rate x time

For Airplane A, we know:

distance = 1662 miles

time = 6 hours

So, we can rearrange the formula to solve for the rate:

rate = distance / time = 1662 / 6 = 277 miles per hour

For Airplane B, we know:

y = 922/3

x = rate of speed over 6 hours

We can use the formula to solve for x:

distance = rate x time

922/3 = x * 6

x = (922/3) / 6 = 153.67 miles per hour

Comparing the rates of the two airplanes, we can see that Airplane A traveled at a faster rate with 277 miles per hour compared to Airplane B's rate of 153.67 miles per hour. Therefore, Airplane A traveled at a faster rate.

User Hesham Shawky
by
7.3k points