Question

A box contains a penny, a nickel, and a dime.

​
​ Find the probability of choosing a dime first and without replacing the dime, choosing a penny.
A 1/6
B 1/7
C 1/8
​D 1/9
​

Answer 1

Answer:When we choose a dime from the box, there are two coins left, one penny and one nickel. Since we do not replace the dime, the probability of choosing a penny next is 1/2.

Therefore, the probability of choosing a dime first and a penny second is:

P(dime first and penny second) = P(dime first) * P(penny second | dime first)

= (1/3) * (1/2)

= 1/6

So, the answer is A. 1/6.

Explanation: