Question

What is the solution set of x2 + 5x- 5 = 0? oss-355 S +385 o sus S* o {stay -S-345 , 30 O S=5+375 5+3/5 2 0 --375 -5 +385 2

Answer 1

Given the quadratic equation:

`x^2+5x-5=0`

Using the general solution for quadratic equations:

`ax^2+bx+c=0\Rightarrow x=(-b\pm√(b^2-4ac))/(2a)`

From the problem, we identify:

`\begin{gathered} a=1 \\ b=5 \\ c=-5 \end{gathered}`

Then:

`x=(-5\pm√(25+20))/(2)=(-5\pm3√(5))/(2)`

And the solution set is:

`\lbrack(-5-3√(5))/(2),(-5+3√(5))/(2)]`