Question

In a population of mendel's garden peas, the frequency of dominant yellow-flowered plants is 50%. The population is in hardy-weinberg equilibrium. What is the frequency of the recessive allele in the population?.

Answer 1

the frequency of the recessive allele in the population is 0.5 or 50%.

Explanation:

In a population in Hardy-Weinberg equilibrium, the frequency of alleles remains constant from generation to generation. According to the Hardy-Weinberg law, if p is the frequency of the dominant allele and q is the frequency of the recessive allele, then:

p + q = 1

and

p^2 + 2pq + q^2 = 1

where p^2 represents the frequency of homozygous dominant individuals, 2pq represents the frequency of heterozygous individuals, and q^2 represents the frequency of homozygous recessive individuals.

Given that the frequency of dominant yellow-flowered plants is 50%, or 0.5, we can assume that p = 0.5. Substituting into the first equation, we get:

0.5 + q = 1

Solving for q, we get:

q = 1 - 0.5

q = 0.5

Therefore, the frequency of the recessive allele in the population is 0.5 or 50%.