Question

How many liters of water must be added to 98.3 grams of naCl to make a 2.18 solution?

Answer 1

Answer

0.77 liters of water

Step by step solved:

To calculate how many liters of water must be added to 98.3 grams of NaCl to make a 2.18 solution, we need to use the formula:

C = n/V

where C is the concentration of the solution in units of moles per liter (M), n is the number of moles of the solute (in this case, NaCl), and V is the volume of the solution in liters.

We are given the mass of NaCl and the desired concentration of the solution, so we can first calculate the number of moles of NaCl that we need:

n = m/M

where m is the mass of NaCl and M is the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol.

n = 98.3 g / 58.44 g/mol ≈ 1.68 mol

Now we can use the formula for concentration to find the volume of the solution:

C = n/V

2.18 mol/L = 1.68 mol / V

V = 1.68 mol / 2.18 mol/L ≈ 0.77 L

So, we need to add 0.77 liters of water to 98.3 grams of NaCl to make a 2.18 solution.

Answer 2

83.22L

Step-by-step explanation:

To solve this problem, we need to use the formula for calculating the concentration of a solution:

concentration = (mass of solute / mass of solvent + mass of solute) x 100

In this case, we know the concentration (2.18), the mass of the solute (98.3 g NaCl), and we want to find the mass of the solvent (water) needed to achieve this concentration.

Let's start by rearranging the formula to solve for the mass of the solvent:

mass of solvent = mass of solute / (concentration / 100 - 1)

Plugging in the values we know:

mass of solvent = 98.3 g / (2.18 / 100 - 1)

mass of solvent = 98.3 g / 1.18

mass of solvent = 83.22 g

So we need 83.22 grams of water to make the solution.

Now we can convert this mass to volume using the density of water, which is 1 g/mL:

volume of water = mass of water / density of water

volume of water = 83.22 g / 1 g/mL

volume of water = 83.22 mL

Therefore, we need to add 83.22 mL of water to 98.3 grams of NaCl to make a 2.18% solution.