Question

What is an equation of the line that passes through the points (−4,−5) and (−8,−2)?

Answer 1

=4y-3x+8=0

Explanation:

The equation of the line is equal to

`(y - y1)/(x - x1) = m`

From the question m is not given

therefore

the Gradient (m).

`(y1 - y2)/(x1 - x2)`

the points

(-4,-5) and (-8,-2)

therefore

`( - 5 - ( - 2))/( - 4 - ( - 8)) \\ = ( - 5 + 2)/( - 4 + 8) \\ = ( - 3)/( - 4) = (3)/(4)`

therefore m = 3/4

the equation of the line

`(y - ( - 5))/(x - ( - 4)) = (3)/(4) \\ (y + 5)/(x + 4) = (3)/(4) \\ 4(y + 5) = 3( x + 4) \\ = 4y + 20 = 3x + 12 \\ 4y = 3x + 12 - 20 \\ 4y = 3x - 8 \\ 4y - 3x + 8 = 0`

Therefore the equation of the line is 4y-3x+8=9