Question

In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)a car that traveled 80 kilometers on 5.0 liters of gasa car that traveled 90 kilometers on 6.0 liters of gasa car that traveled 50 kilometers on 4.0 liters of gasa car that traveled 70 kilometers on 5.0 liters of gas

Answer 1

The efficiency of a car is the measure of how far can it travel in one liter of gas.

Thus the efficiency can be calculated as,

`\eta=\frac{\text{distance traveled}}{volume\text{ of the gas}}`

a. Given, the car traveled for d=80 km in V=5.0 L of gas.

Thus the efficiency in this case is,

`\begin{gathered} \eta_a=(80)/(5) \\ =16\text{ km/L} \end{gathered}`

b.

Given, the car traveled for 90 km using 6.0 L of gas

Thus the efficiency in this case is,

`\begin{gathered} \eta_b=(90)/(6) \\ =15\text{ km/L} \end{gathered}`

c.

Given, the car travels for 50 km on 4.0 L of gas.

Thus the efficiency of the car, in this case, is given by,

`\begin{gathered} \eta_c=(50)/(4) \\ =12.5\text{ km/L} \end{gathered}`

d.

Given,

The car travels for a distance of 70 km using 5.0 L of gas.

Therefore, the efficiency of the car, in this case, is given by,

`\begin{gathered} \eta_d=(70)/(5) \\ =14\text{ km/L} \end{gathered}`

Thus on comparing, the car in the option a achieved the greatest efficiency.

Therefore, the correct answer is option a.