Answer: To find the equation of the straight line parallel to the given line 4x+3y=1 and passing through the point (0,1), we can use the fact that parallel lines have the same slope.
First, we need to rearrange the given line into slope-intercept form, y = mx + b, where m is the slope of the line:
4x + 3y = 1
3y = -4x + 1
y = (-4/3)x + 1/3
Therefore, the slope of the given line is -4/3. Now, we can use this slope and the point (0,1) to find the equation of the line we're looking for:
y - y1 = m(x - x1) (point-slope form)
y - 1 = (-4/3)(x - 0)
y - 1 = (-4/3)x
y = (-4/3)x + 1
So the equation of the straight line parallel to 4x+3y=1 and passing through point (0,1) is y = (-4/3)x + 1.
Explanation: