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How many points of inflection will f(x) = 3x^4 + 2x^3 - 5x - 12 have

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Final answer:

To determine the number of points of inflection for f(x) = 3x^4 + 2x^3 - 5x - 12, calculate the second derivative and find where it changes sign. After finding the second derivative is zero at x = 0 and x = -1/3, checking around these points for a sign change will confirm any points of inflection.

Step-by-step explanation:

To find the number of points of inflection for the function f(x) = 3x^4 + 2x^3 - 5x - 12, we need to investigate the concavity changes of the function. A point of inflection occurs where the second derivative changes sign, indicating a change in concavity.

First, compute the first derivative of f(x):

f'(x) = d/dx (3x^4 + 2x^3 - 5x - 12) = 12x^3 + 6x^2 - 5

Next, compute the second derivative: f''(x) = d/dx (12x^3 + 6x^2 - 5) = 36x^2 + 12x

Then, find the values of x where f''(x) is zero to determine possible points of inflection:

  • Set f''(x) = 0
  • 0 = 36x^2 + 12x
  • x(36x + 12) = 0
  • x = 0 or x = -1/3
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