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A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 400 ft. After 40 minutes the bell is at a depth of 1400 ft. Use the ordered pairs (10, 400) and (40, 1400 to determine the average rate to lower the bell per minute.

User Vishnu Upadhyay
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1 Answer

10 votes
10 votes
Answer:

The average rate to lower the ball per minute is 100/3

Step-by-step explanation:

Given the ordered pairs (10, 400) and (40, 1400)

The average rate of change is given as:


\begin{gathered} (y_2-y_1)/(x_2-x_1) \\ \\ \text{where} \\ x_1=10 \\ y_1=400 \\ x_2=40 \\ y_2=1400 \end{gathered}

Using these parameters, we have:


\begin{gathered} (1400-400)/(40-10) \\ \\ =(1000)/(30)=(100)/(3) \end{gathered}

User Royal
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