Final answer:
Carol can play at most 5 games of ring toss based on her budget constraint.
Step-by-step explanation:
To find how many games of ring toss Carol can play, we can set up an inequality based on her budget. Let x be the number of games she can play. The cost of playing one game is $3, so the total cost of x games is 3x. We know that Carol has at most $15, so we can write the inequality as:
3x ≤ 15
To solve this inequality, we divide both sides by 3 to isolate x:
x ≤ 5
Therefore, Carol can play at most 5 games of ring toss.