Question

Suppose 0. 800 m naoh (aq) is used to titrate 50. 00 ml of an unknown hcl (aq) solution. If it takes 15. 00 ml of the naoh (aq) to reach the end point, what was the initial concentration (in m) of the hcl solution? enter your unrounded answer.

Answer 1

Step-by-step explanation:

The balanced chemical equation for the reaction between NaOH and HCl is:

NaOH + HCl → NaCl + H2O

According to the balanced equation, one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of H2O. Therefore, the number of moles of NaOH used to titrate the HCl solution is equal to the number of moles of HCl in the solution.

First, we need to calculate the number of moles of NaOH used in the titration:

moles of NaOH = concentration of NaOH × volume of NaOH used

Substituting the values, we get:

moles of NaOH = 0.800 M × 0.01500 L = 0.0120 moles

Since NaOH and HCl react in a 1:1 molar ratio, the number of moles of HCl in the solution is also 0.0120 moles.

Now, we can calculate the initial concentration of the HCl solution using the following formula:

initial concentration of HCl = moles of HCl / volume of HCl used

The volume of HCl used is 50.00 mL, which is equal to 0.05000 L. Therefore, we get:

initial concentration of HCl = 0.0120 moles / 0.05000 L = 0.240 M

Therefore, the initial concentration of the HCl solution is 0.240 M.