Question

A line passes through the point (-9, 5) and has a slope of 4/3. Write an equation in point-slope form for this line.

Answer 1

The equation of a line in point-slope form is given by;

`\begin{gathered} y-y_1=m(x-x_1) \\ \\ \text{where m is the slope} \\ \text{and } \\ (x_1,y_1)\text{ is the point} \\ m=(4)/(3) \\ x_1=-9 \\ y_1=5 \end{gathered}`

Substituting these values into the formula;

`\begin{gathered} y-y_1=m(x-x_1) \\ y-5=(4)/(3)(x-(-9)) \\ y-5=(4)/(3)(x+9) \end{gathered}`

Therefore, the equation of the line in point-slope form is;

`y-5=(4)/(3)(x+9)`