Answer:
Step-by-step explanation:
To calculate the molarity of the solution, we first need to determine the mass of calcium chloride (CaCl2) in 100 g of the solution.
If the solution is 22.3% calcium chloride by mass, this means that there are 22.3 g of CaCl2 in 100 g of the solution.
We can use the density of the solution to convert 100 g of the solution to its volume:
volume of 100 g of the solution = mass of the solution / density of the solution
volume of 100 g of the solution = 100 g / 1.20 g/mL = 83.3 mL
Now, we can calculate the molarity of the solution using the following formula:
molarity = moles of solute / volume of solution (in L)
The molar mass of CaCl2 is 40.08 + 2(35.45) = 110.98 g/mol. Therefore, the number of moles of CaCl2 in 22.3 g of the solution is:
moles of CaCl2 = 22.3 g / 110.98 g/mol = 0.2008 mol
The volume of the solution containing 22.3 g of CaCl2 is:
volume of solution = 83.3 mL / 1000 mL/L = 0.0833 L
Substituting these values into the formula for molarity, we get:
molarity = 0.2008 mol / 0.0833 L = 2.41 M
Therefore, the molarity of the aqueous solution that is 22.3% by mass calcium chloride is 2.41 M.