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A bag contains 8 red, 10 pink, 6 purple, 5 green, and 11 blue jolly ranchers. What is the probability of selecting a red, then a green without replacement?

User Ingo
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1 Answer

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Answer: The probability of selecting a red, then a green without replacement is 0.0256 or approximately 2.56%.

Explanation:

The probability of selecting a red jolly rancher on the first draw without replacement is:

P(Red on 1st draw) = (number of red jolly ranchers) / (total number of jolly ranchers)

P(Red on 1st draw) = 8 / (8+10+6+5+11)

P(Red on 1st draw) = 8 / 40

P(Red on 1st draw) = 0.2

After taking out one red jolly rancher, there are now 39 jolly ranchers left in the bag. The probability of selecting a green jolly rancher on the second draw without replacement is:

P(Green on 2nd draw) = (number of green jolly ranchers left)/(total number of jolly ranchers left)

P(Green on 2nd draw) = 5/(39)

P(Green on 2nd draw) = 5 / 39

The probability of selecting a red, then a green without replacement is the product of the two probabilities:

P(Red, then Green) = P(Red on 1st draw) x P(Green on 2nd draw)

P(Red, then Green) = 0.2 x 5/39

P(Red, then Green) = 0.0256

The probability of selecting a red, then a green without replacement is 0.0256 or approximately 2.56%.

User Korin
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