Question

A line has a slope of 3 and passes through the point (-2, -10)

Answer 1

We'll use the point-slope form to find the equation for the such line.

The point-slope form is given by the following :

y-y₁=m(x-x₁)

where

x₁ and y₁ are the fixed points on a line known to us.

Explanation:

m = 3 (given)

(-2,-10) are the fixed points which lie on the given line.

Putting the following values in the point-slope form gives us the:

y - (-2) = 3*(x-(-10))

=> y +2 = 3*(x+10) => y + 2 = 3x + 30

=> y - 3x = 28 .

y - 3x = 28 is the equation of the line thus.

Answer 2

y = 3x - 4

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = 3 , then

y = 3x + c ← is the partial equation

to find c substitute (- 2, - 10 ) into the partial equation

- 10 = 3(- 2) + c = - 6 + c ( add 6 to both sides )

- 4 = c

y = 3x - 4 ← equation of line