Answer:
4Al(s) + 3O2(g) → 2Al2O3(s)
Step-by-step explanation:
The balanced equation for the formation of aluminum oxide is:
4Al(s) + 3O2(g) → 2Al2O3(s)
From this equation, we can derive several mole ratios:
- For every 4 moles of aluminum, 2 moles of aluminum oxide are formed.
- For every 3 moles of oxygen, 2 moles of aluminum oxide are formed.
- For every 2 moles of aluminum oxide formed, 4 moles of aluminum were used.
- For every 2 moles of aluminum oxide formed, 3 moles of oxygen were used.
- The ratio of aluminum to oxygen used in the reaction is 4:3.
- The ratio of aluminum oxide to oxygen used in the reaction is 2:3.