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Cos^2x+sinx=1 can someone help me

2 Answers

1 vote

Answer:

x = 90° or π/2 radians

Explanation:

We are given
cos²(x) + sin(x) = 1 [1]

The following identity is true:
cos²(x) + sin²(x) = 1 [2]

Subtract [1] from [2]
cos²(x) + sin²(x) - (cos²(x) + sin(x)) = 1 - 1

cos²(x) + sin²(x) - cos²(x) - sin(x) = 0

==> sin²(x) - sin(x) = 0

==> sin²(x) = sin(x)

Divide both sides by sin(x) to get

sin²(x)/sin(x) = sin(x)/sin(x)

==> sin(x) = 1

x = sin⁻¹(1)

x = 90° or π/2 radians

User Pavel Zimogorov
by
8.1k points
5 votes

Answer:

cos²x+sinx = 1

sinx = 1 - cos²x

sinx = sin²x

sinx = 1

x = 90

User Jens Bannmann
by
7.6k points