Question

Solve the equations in the system y=x^2-3,2x-y=3

Answer 1

Explanation:

Isolate the last system for y

`2x - y = 3`

`- y = - 2x + 3`

`y = 2x - 3`

Set each equation equal to each other

`{x}^(2) - 3 = 2x - 3`

`{x}^(2) - 2x = 0`

`x(x - 2) = 0`

`x = 0`

`x = 2`

Plug in both x values to get their associated y values

`{0}^(2) - 3 = - 3`

So one solution is (0,-3)

`{2}^(2) - 3 = 1`

Another solution is (2,1)

Answer 2

(x1,y1)=(0,-3)

(X2,y2)=(2,1)

Explanation: