Answer:
a. Hooke's law is a principle in physics that states that the force required to extend or compress a spring or elastic material is directly proportional to the displacement of its end or deformation.
b. The formula for resistance of a wire is given by:
R = (ρL)/A
where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
Given L = 10m, A = 0.1 mm² = 0.1 x 10^-6 m², and ρ = 50 µcm = 50 x 10^-8 Ωm, we have:
R = (50 x 10^-8 x 10) / (0.1 x 10^-6)
R = 5 Ω
Therefore, the resistance of the wire is 5 Ω.
The formula for Young's modulus is given by:
Y = F L / A ΔL
where Y is Young's modulus, F is force, L is length, A is cross-sectional area, and ΔL is the change in length.
Given F = 2 kgf = 2 x 9.81 N, L = 2 m, d = 0.64 mm = 0.64 x 10^-3 m, and ΔL = 0.60 mm = 0.60 x 10^-3 m, we have:
A = πd²/4 = π(0.64 x 10^-3)²/4 = 3.21 x 10^-7 m²
Y = (2 x 9.81 x 2) / (3.21 x 10^-7 x 0.60 x 10^-3)
Y ≈ 1.24 x 10^11 N/m²
Therefore, the Young's modulus of the wire is approximately 1.24 x 10^11 N/m².
Step-by-step explanation: