Answer:
C₉H₂₀ (l) + 14O₂ (g) → 9CO₂ (g) + 10H₂O (g)
Step-by-step explanation:
CH₃(CH₂)₇CH₃ (l) + O₂ (g) → CO₂ (g) + H₂O (g)
C₉H₂₀ (l) + O₂ (g) → CO₂ (g) + H₂O (g)
Simply balance each element in turn and then move on to the next one:
1. Balance the C's
C₉H₂₀ (l) + O₂ (g) → 9CO₂ (g) + H₂O (g)
2. Balance H's
C₉H₂₀ (l) + O₂ (g) → 9CO₂ (g) + 10H₂O (g)
3. Balance O's
C₉H₂₀ (l) + 14O₂ (g) → 9CO₂ (g) + 10H₂O (g)
Note how I started with C's as there is only one reagent and one product with C, then the H's, once again only one reagent and one product with H;
These I would say are the easiest so you should start with them;
The O's, on the other hand, there are 2 products with O so leave this one till later;
Moreover, O₂ on the left is on its own, unbonded with any other element so it is easy to balance and can be left to the end.
Tip: Remember to bear in mind the changes in each element as a result of balancing in the previous step