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How many grams are in 1.62 moles Fe2(SO3)3

User Sirgeorge
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1 Answer

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20 votes

Answer:

570. g Fe₂(SO₃)₃

General Formulas and Concepts:
Atomic Structure

  • Reading a Periodic Table
  • Compounds

Stoichiometry

  • Using Dimensional Analysis
  • Molar Ratio

Step-by-step explanation:

Step 1: Define

1.62 moles Fe₂(SO₃)₃

Step 2: Identify

Molar Mass of Fe: 55.85 g/mol

Molar Mass of S: 32.07 g/mol

Molar Mass of O: 16.00 g/mol

Molar Mass of Fe₂(SO₃)₃: 2(55.85) + 3(32.07) + 9(16.00) = 351.91 g/mol

Step 3: Convert

Use dimensional analysis.

  1. Set up:
    \displaystyle 1.62 \ \text{moles} \ Fe_2(SO_3)_3 \bigg( \frac{351.91 \ g \ Fe_2(SO_3)_3}{1 \ \text{mole} \ Fe_2(SO_3)_3} \bigg)
  2. Evaluate [Cancel out units]: 570.094 g Fe₂(SO₃)₃
  3. [Round] Significant Figures: 570.094 g Fe₂(SO₃)₃ ≈ 570. g Fe₂(SO₃)₃

Topic: Chemistry

Unit: Atomic Structure/Stoichiometry

User Menion Asamm
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