Question

A sample of chlorine gas was cooled from 380 k to -1 c. its new volume is 75 ml. what was its original volume?

Answer 1

The formula for volume change due to temperature change is V1/T1 = V2/T2, where V1 is the original volume and T1 is the original temperature in Kelvin. Substituting the given values, we get V1 = 380 x 75 / 274 = 299.125 ml. Therefore, the original volume of the sample of chlorine gas was 299.125 ml.

Answer 2

Step-by-step explanation:

Given:

• T1 = 380K

• T2 = -1°C = 272K

• V2 = 75mL

Finding :

• V1

Solution :

According to Charles law

`\large\sf{ (V_(1))/(T_(1)) = (V_(2))/(T_(2)) (pressure~ constant)}`

`\large\implies\sf{ (V_(1))/(380) = (75)/(272) }`

`\large\implies\sf{ V_(1) = (380 * 75)/(272)}`

`\large\implies\sf{ V_(1) = (380 * 75)/(272)}`

`\large\implies\sf{ V_(1) = (28500)/(272)}`

`\large\implies\bf{ V_(1) = 104.78 mL}`

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