Answer:
Step-by-step explanation:
To solve this problem, we can use the principle of work: W = F x d, where W is the work done, F is the force applied, and d is the distance over which the force is applied.
In this case, the effort force is 250 N and the effort distance is unknown. Let's call it Ae. The load distance is 25 cm, which is 0.25 m. We also know that the work done by the effort force is equal to the work done by the load force:
Effort work = Load work
250 N x Ae = Load x 0.25 m
Solving for Load, we get:
Load = (250 N x Ae) / 0.25 m
We don't have a value for Ae, so we cannot solve for Load yet. However, we can use another principle of work: the principle of mechanical advantage. The mechanical advantage (MA) is the ratio of the load force to the effort force. In this case, the load force is Load and the effort force is 250 N. The MA is:
MA = Load / Effort = Load / 250 N
We know that the load distance is 0.25 m and the effort distance is Ae, so the MA is also:
MA = Load distance / Effort distance = 0.25 m / Ae
Setting these two expressions for MA equal to each other, we get:
Load / 250 N = 0.25 m / Ae
Solving for Load, we get:
Load = (0.25 m / Ae) x 250 N
Now we can substitute this expression for Load into the earlier equation:
(0.25 m / Ae) x 250 N = (250 N x Ae) / 0.25 m
Simplifying, we get:
Ae^2 = 0.25 m^2
Ae = 0.5 m
Now we can substitute this value for Ae into the expression for Load:
Load = (250 N x 0.5 m) / 0.25 m = 500 N
Therefore, the load is 500 N.