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Find the equation of a line that passes through (-3,-17) and (2,8)

User Pravy
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1 Answer

5 votes

Answer:

Explanation:

To find the equation of a line that passes through two given points, we can use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

where (x1, y1) is one of the given points, and m is the slope of the line.

First, we can find the slope of the line by using the two given points:

m = (y2 - y1)/(x2 - x1)

m = (8 - (-17))/(2 - (-3))

m = 25/5

m = 5

Now that we have the slope, we can use either of the two given points in the point-slope form of the equation of a line. Let's use the point (-3, -17):

y - y1 = m(x - x1)

y - (-17) = 5(x - (-3))

y + 17 = 5(x + 3)

This is the equation of the line in point-slope form. We can simplify it by distributing the 5:

y + 17 = 5x + 15

Then, we can solve for y by subtracting 17 from both sides:

y = 5x - 2

This is the equation of the line in slope-intercept form, where the slope is 5 and the y-intercept is -2. Therefore, the equation of the line that passes through the points (-3, -17) and (2, 8) is y = 5x - 2.

User Glowka
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