Final Answer:
(a) The carrying capacity is 2000.
(b) P'(0) = 32.
(c) The population will reach 50% of the carrying capacity after approximately 6.91 years.
Step-by-step explanation:
The carrying capacity (K) in this scenario is the population size at which the growth rate becomes zero. It can be determined by setting dP/dt = 0. At equilibrium, 0.8P - 0.001P^2 = 0, and solving this equation gives K = 2000 as the carrying capacity.
To find P'(0), we can use the initial population value (P(0) = 40) and substitute it into the differential equation dP/dt = 0.8P - 0.001P^2. Evaluating P'(0) provides the instantaneous rate of change at time t = 0, yielding P'(0) = 32.
The time it takes for the population to reach 50% of the carrying capacity can be calculated using the logistic growth model. To find this time (t_50), the formula t_50 = (1/0.8) * ln((K - P(0))/(P(0))) is employed, where ln represents the natural logarithm. Substituting the given values, t_50 ≈ (1/0.8) * ln((2000 - 40)/(40)), which approximately equals 6.91 years.
By solving the differential equation and interpreting the results, we ascertain the carrying capacity, the initial rate of change, and the time it takes for the population to reach 50% of the carrying capacity.